Monty Hall Problem

I hate probability but you can sometimes pose very simple questions with interesting answers.

Suppose you’re on a game show, and you’re given the choice of three doors: Behind one door is a car; behind the others, goats. You pick a door, say No. 1, and the host, who knows what’s behind the doors, opens another door, say No. 3, which has a goat. He then says to you, “Do you want to pick door No. 2?” Is it to your advantage to switch your choice?

How would you answer the question? Can you also explain your reasoning without cheating? I wonder if I should post more random/simple math problems

4 Responses to “Monty Hall Problem”

  1. goat says:

    No, cuz behind that door maybe another goat…btw! You were supposed to build me a doomsday device…baaaaahhh!~

    • Krishna says:

      You always switch doors.

      So if you switch doors and lose, that can only happen if you started off by picking the car, which has probability 1/3. Now if you pick a goat, the host opens up the door with the other goat, then switching doors means you pick the car. So that happens 2/3 times.

      Thus the odds of winning after switching doors is 2/3.

  2. Leave A. Reply says:

    Goats aren’t so bad really.
    They make excellent cheese, and can mow your lawn for you

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